How to specify pattern dynamically using file and get files according to pattern from that directory?

Question

I am newbie of shell script. Correct if I am wrong.

I have one file called ignorefileslist in which it has file's names and patterns like /trunk/* means ignore all files from trunk.

I am able to get line of file which holds this pattern but unable to find out how to execute those pattern to get files matching that pattern. For example files inside /trunk folder for /trunk/* pattern.

ignorefileslist.txt :

/.settings
/.project
/branches/staging/test.php
/trunk/index.php
/trunk/*.php
/trunk/*

Here is my code :

if grep -q "*" "$HOME/$REPONAME/ignorablefileslist.txt";then

   filewithpattern=`cat $HOME/$REPONAME/ignorablefileslist.txt | grep "*" `

   echo "It contains pattern $filewithpattern"    
fi

Output :

It contains pattern /trunk/*.php /trunk/*

How can I both /trunk/* and /trunk/*.php regex to get files accordingly?

Answer 1

如下更改grep命令，以打印包含/trunk/*或/trunk/*.php字符串的文件名。

grep -lP '/trunk/\*(\.php)?' *.*

Answer 2

如果由于某种原因需要保持条件语句完整，则可以使用循环和进程替换来避免子shell。

if grep -q "*" ignorefileslist.txt; then while read filewithpattern; do echo "It contains pattern $filewithpattern"; done < <( grep "*" ignorefileslist.txt ); fi