I am trying to get file paths of all .txt files in a directory and replace the root directory of each file and pad zeros for file path with different padding lengths. Consider an example of the file list:
./Old directory/ABC 01/XYZ 1 - M 1.txt
./Old directory/ABC 01/XYZ 1 - M 2.txt
./Old directory/ABC 01/XYZ 1 - M 3.txt
Now a require a Python code to give me this output:
./New directory/ABC 00001/XYZ 0001 - M 001.txt
./New directory/ABC 00001/XYZ 0001 - M 002.txt
./New directory/ABC 00001/XYZ 0001 - M 003.txt
The reproducible code (my effort):
import os
import re
files = []
for root, directories, files in os.walk('./Old directory'):
files = sorted([f for f in files if os.path.splitext(f)[1] in ('.txt')])
for file in files:
files.append(os.path.join(root, file))
for file in files:
file.replace('./Old directory', './New directory')
I doubt that it is that easy, but it looks like you are very close.
import re
...
for file in files:
file = file.replace('./Old directory', './New directory')
p = re.compile(ur'(\d+)')
file = re.sub(p, u"000$1", file)
It is fatal to use the same variable files
for two different purposes in your code - I changed one instance to filenames
, and I complemented the code to do the zero-padding.
import os
import re
filenames = []
for root, directories, files in os.walk('./Old directory'):
files = sorted([f for f in files if os.path.splitext(f)[1] in ('.txt')])
for file in files:
filenames.append(os.path.join(root, file))
def padzeros(s, m, g, width): # pad the group g of match m in string s
return s[:m.start(g)]+m.group(g).zfill(width)+s[m.end(g):]
for file in filenames:
file = file.replace('./Old directory', './New directory')
m = re.search(r'\D+(\d+)\D+(\d+)\D+(\d+)', file)
# important: pad from last to first match
file = padzeros(file, m, 3, 3)
file = padzeros(file, m, 2, 4)
file = padzeros(file, m, 1, 5)
print file
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