Create new variables based upon specific values

Question

I read up on regular expressions and Hadley Wickham's stringr and dplyr packages but can't figure out how to get this to work.

I have library circulation data in a data frame, with the call number as a character variable. I'd like to take the initial capital letters and make that a new variable and the digits between the letters and period into a second new variable.

Call_Num
HV5822.H4 C47 Circulating Collection, 3rd Floor
QE511.4 .G53 1982 Circulating Collection, 3rd Floor
TL515 .M63 Circulating Collection, 3rd Floor
D753 .F4 Circulating Collection, 3rd Floor
DB89.F7 D4 Circulating Collection, 3rd Floor 

Answer 1

Using the stringi package, this would be one option. Since your target stays at the beginning of the strings, stri_extract_first() would work pretty well. [:alpha:]{1,} indicates alphabet sequences which contain more than one alphabet. With stri_extract_first() , you can identify the first alphabet sequence. Likewise, you can find the first sequence of numbers with stri_extract_first(x, regex = "\\\\d{1,}") .

x <- c("HV5822.H4 C47 Circulating Collection, 3rd Floor",
       "QE511.4 .G53 1982 Circulating Collection, 3rd Floor",
       "TL515 .M63 Circulating Collection, 3rd Floor",
       "D753 .F4 Circulating Collection, 3rd Floor",
       "DB89.F7 D4 Circulating Collection, 3rd Floor")

library(stringi)

data.frame(alpha = stri_extract_first(x, regex = "[:alpha:]{1,}"), 
           number = stri_extract_first(x, regex = "\\d{1,}"))

#  alpha number
#1    HV   5822
#2    QE    511
#3    TL    515
#4     D    753
#5    DB     89

Answer 2

what about

rl <- read.table(header = TRUE, text = "Call_Num
'HV5822.H4 C47 Circulating Collection, 3rd Floor'
                 'QE511.4 .G53 1982 Circulating Collection, 3rd Floor'
                 'TL515 .M63 Circulating Collection, 3rd Floor'
                 'D753 .F4 Circulating Collection, 3rd Floor'
                 'DB89.F7 D4 Circulating Collection, 3rd Floor'",
                 stringsAsFactors = FALSE)
cbind(rl, read.table(text = gsub('([A-Z]+)([0-9]+).*', '\\1 \\2', rl$Call_Num)))

#                                              Call_Num V1   V2
# 1     HV5822.H4 C47 Circulating Collection, 3rd Floor HV 5822
# 2 QE511.4 .G53 1982 Circulating Collection, 3rd Floor QE  511
# 3        TL515 .M63 Circulating Collection, 3rd Floor TL  515
# 4          D753 .F4 Circulating Collection, 3rd Floor  D  753
# 5        DB89.F7 D4 Circulating Collection, 3rd Floor DB   89

Answer 3

If you want to use stringr , the solution would probably look something like this:

df <- data.frame(Call_Num = c("HV5822.H4 C47 Circulating Collection, 3rd Floor", "QE511.4 .G53 1982 Circulating Collection, 3rd Floor", "TL515 .M63 Circulating Collection, 3rd Floor", "D753 .F4 Circulating Collection, 3rd Floor", "DB89.F7 D4 Circulating Collection, 3rd Floor"))

require(stringr)

matches = str_match(df$Call_Num, "([A-Z]+)(\\d+)\\s*\\.")
df2 <- data.frame(df, letter=matches[,2], number=matches[,3])
df2
##                                                  Call_Num letter number
## 1     HV5822.H4 C47 Circulating Collection, 3rd Floor     HV   5822
## 2 QE511.4 .G53 1982 Circulating Collection, 3rd Floor     QE    511
## 3        TL515 .M63 Circulating Collection, 3rd Floor     TL    515
## 4          D753 .F4 Circulating Collection, 3rd Floor      D    753
## 5        DB89.F7 D4 Circulating Collection, 3rd Floor     DB     89

I don't think that sticking the str_match() call into mutate() of dplyr is worth the effort, so I'd just leave it at that. Or use rawr's solution.

Answer 4

You can use strapply from the gsubfn package:

library(gsubfn)

m <- strapply(as.character(df$Call_Num), '^([A-Z]+)(\\d+)', 
     ~ c(id = x, num = y), simplify = rbind)

X <- as.data.frame(m, stringsAsFactors = FALSE)

#   id  num
# 1 HV 5822
# 2 QE  511
# 3 TL  515
# 4  D  753
# 5 DB   89