My regular expression is of format "Exit* Order*". When i use in java its not working as expected.
String pattern = "Exit* Order*";
String ipLine = "Exiting orders";
Match: NO
String pattern = "Exit Order";
String ipLine = "Exit order";
Match: Yes.
Java Code: Pattern patrn = Pattern.compile(pattern,Pattern.CASE_INSENSITIVE); Matcher match = patrn.matcher(ipLine);
Can any one let me know what should be the pattern in such cases.
I believe you are looking for something like:
"Exit.* Order.*"
or maybe something instead of .*
, eg \\S*
, \\w*
, [A-Za-z]*
.
Your current regular expression is looking for zero or more t
and r
on the ends of the words, eg it would match
Exi Orde
Exit Orde
Exitt Orde
Exi Order
Exi Orderr
...
Exit\\w* Order\\w*
You should use this. .*
can match much more than intended.use i
or ignorecase
flag
It seems like you just want to match "Exit Order" case-insensitively:
Try this:
if (str.matches("(?i)exit order"))
Or to restrict the match to just your examples, where the "O" of "Order may be "o", use:
if (str.matches("Exit [Oo]rder"))
Java does not use Linux regexp expression: http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
Use this:
String pattern = "Exit.* Order.*";
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