How to split string on second character match in python?

Question

I have my string in variable:

query = 'name=Alan age=23, name=Jake age=24'

how do I split my string on name=Jake instead of name=Alan ? Don't suggest query.split(name=Alan) , it won't work in my case.

I need something that will skip first name and continue searching for second, and then do split. So, how can i do that?

Answer 1

使用query.split(',')[1].split('name')

Answer 2

You can try splitting on the comma and then on the spaces like so:

query = 'name=Alan age=23, name=Jake age=24'
query_split = [x.strip() for x in query.split(",")]
names = [a.split(" ")[0][5:] for a in query_split]
print(names)

['Alan', 'Jake']

With this you don't need multiple variables since all your names will be in the list names , you can reference them by names[0] , names[1] and so on for any given number of names.

Answer 3

Try this:

query = 'name=Alan age=23, name=Jake age=24'
names = [y.split(" ")[0][5:] for y in (x.strip() for x in query.split(","))]
print(names)

Output:

['Alan', 'Jake']