Passing an Integer with Exception in Java

Question

I have following exception

public class MyException extends SecurityException{
      public MyException( String s ) { super( s ) ; }
}

where SecurityException is java.lang.SecurityException .

whenever I throw MyException("Message"); , I can get the message.

Now, in MyException I want to pass an integer value with MyException and access that integer where I am catching this MyException .

How do I do that ?

Answer 1

public class MyException extends SecurityException{
  private int i;
  public MyException(String s, int i) { 
     super(s);
     this.i = i;
  }

  public int getI() { return i; }
}

Answer 2

You can specify a member variable in MyException class and use it at catch point. Something like -

public class MyException extends SecurityException{
  private Integer value;
  public MyException( Integer n, String s ) { 
       super(s) ;
       value = n;
  }
  public Integer getValue() {
       return value;
  }
}