How do I call upon ALL the elements of my array in python?

Question

I am trying to get my code to identify everything in my array however what I thought you should do is not working...Any suggestions???

Here is my code:

version = ['4','4s','5','5C','5S','6','6 Plus','6+','6S','6S', Plus','6S+','SE','7','7 Plus','7+']

if make == version[0-14]:
    print (m

Answer 1

I think what you're trying to do is see if make is in your list. The way you do this in Python is with the in operator:

version = ['4','4s','5','5C','5S','6','6 Plus','6+','6S','6S', 'Plus','6S+','SE','7','7 Plus','7+']

if make in version:
    print (make)

Answer 2

try:

m = '4'
if any([m == v for v in version[0:14]]):
    print(m)

Answer 3

It's not entirely clear what you are trying to accomplish from your sample. Are you just trying to see if the value of make exists in the version list? If so, change this:

if make == version[0-14]:

to this:

if make in version:

Answer 4

There is missing a ' in front of the second "Plus"

version = ['4','4s','5','5C','5S','6','6 Plus','6+','6S','6S', 'Plus','6S+','SE','7','7 Plus','7+']

if make == version[0-14]:
    print (m