How to store string which contains ; to String[] in java

Question

I have input string in

String x = "સ્થિતિ";  
// WHich is Hex NCR cooded string contains & # x 0 and ; for e.g. &#x0AB ;

String sFinalData = 87508~~~~20~false@87512~x~~~22~true

I am using following code.

String[] sPropertyString = sFinalData.split("@");
for(int iter=0;iter<sPropertyString.length;iter++){
   String[] sProperty = sPropertyString[iter].split("~");
   sPropertyName = sProperty[1];
   System.out.println("O/P..."+sPropertyName );
}

But for above code it is showing array index out of bound.

I need to store this Hex NCR string to database.

Any suggestion?

Answer 1

sPropertyName = sProperty[1]; is array index out of bound Exception come from this line? why you use index 1 , maybe sProperty.length is 1.then the max index is 0.