I need to match the string "foo" from a string with this format:
string = "/foo/boo/poo"
I tied this code:
poo = "poo"
foo = re.match('.*(?=/' + re.escape(poo) + ')', string).group(0)
and it gives me /foo/boo
as the content of the variable foo (instead of just foo/boo
).
I tried this code:
poo = "poo"
foo = re.match('(?=/).*(?=/' + re.escape(poo) + ')', string).group(0)
and I'm getting the same output ( /foo/boo
instead of foo/boo
).
How can I match only the foo/boo
part?
You are missing a <
in your lookbehind!
Lookbehinds look like this:
(?<=...)
not like this:
(?=...)
That would be a look ahead !
So,
(?<=/).*(?=/poo)
Hey try the following regex:
(?<=/).*(?=/poo)
^^^^^^
It will not take into account your first slash in the result.
Tested regex101 : https://regex101.com/r/yzMkTg/1
Transform your code in the following way and it should work:
poo = "poo"
foo = re.match('(?<=/).*(?=/' + re.escape(poo) + ')', string).group(0)
Have a quick look at this link for more information about the behavior of Positive lookahead
and Positive lookbehind
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.