Remove fraction from an address in pandas data frame

Question

I have a dataframe in pandas which I would like to remove fractions from the column with addresses. I can't figure out the correct regress implementation to remove them.

The sample addresses look like:

580 1/4 Broadway Street

85 1/4 Grand Street

Two things, I'm not sure how to loop through the dataframe to remove the special characters.

And two what is the correct regex function and how do I regroup the flags?

I came up with

"^(. )\\d+/\\d+\\s(. )" and "\\1\\2" to group the flags together

Or is there just a better way to do this?

Answer 1

Use str.replace , you don't need matching groups at all.

df.address.str.replace(r'\d+\/\d+', '')

0    580  Broadway Street
1        85  Grand Street
Name: address, dtype: object