I have an array containing [name, surname, int1, int2]
elements and I need to sort it by this order:
By int1
(decreasing).
If int1
is the same, sort by name
in "reversed"-alphabetical order.
If name
is the same, order by surname
in alphabetical order.
So I have this:
print(sorted(a, key = lambda x: [-int(x[2]), x[0], x[1]]))
And I have no idea how to sort x[0]
in reverse-alphabetical order -x[0], x[0][::-1]
doesn't work for me.
Example:
[('Petia', 'Anja', 3, 0),
('Vasia', 'Katia', 3, 0),
('Petia', 'Katia', 3, 0),
('Kolia', 'Alexey', 10, 0),
('Yana', 'Anja', 10, 0)]
to
[('Yana', 'Anja', 10, 0),
('Kolia', 'Alexey', 10, 0),
('Vasia', 'Katia', 3, 0),
('Petia', 'Anja', 3, 0),
('Petia', 'Katia', 3, 0)]
You could create a class with an implementation for <
( <
is all CPythons sorted
requires - if you're using another Python implementation you might need additional comparison operators). That allows full control over the "ordering". For example:
class Sorter(object):
def __init__(self, tup):
self.name, self.surname, self.int1, self.int2 = tup
def __lt__(self, other):
# Just to make the logic clearer, in practise you could do nest the ifs
# to avoid computing self.int1 == other.int1 twice
if self.int1 == other.int1 and self.name == other.name:
return self.surname < other.surname
elif self.int1 == other.int1:
return self.name > other.name
else:
return self.int1 > other.int1
Then use that as key
for sorted
:
>>> sorted(a, key=Sorter)
[('Yana', 'Anja', 10, 0),
('Kolia', 'Alexey', 10, 0),
('Vasia', 'Katia', 3, 0),
('Petia', 'Anja', 3, 0),
('Petia', 'Katia', 3, 0)]
>>> intab='abcdefghijklmnopqrstuvwxyz'
>>> tab = string.maketrans(intab+intab.upper(), intab[::-1]+intab.upper()[::-1])
>>>
>>> slst = sorted(lst, key = lambda x: [-int(x[2]), x[0].translate(tab), x[1]])
>>> pprint(slst)
[('Yana', 'Anja', 10, 0),
('Kolia', 'Alexey', 10, 0),
('Vasia', 'Katia', 3, 0),
('Petia', 'Anja', 3, 0),
('Petia', 'Katia', 3, 0)]
>>>
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