Convert text file to a dictionary of key strings and value integers

Question

i have a text file of numbers like so

text.file '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9 i would like to convert this to an array like so:

myary= {'1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9} but i want the keys to be a string and the values to be integer

i think i am able to get all of this as a string but that is not what i want i want it to be seprate

Answer 1

using ast.literal_eval

import ast
txt = "'1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9"
print (ast.literal_eval('{' + txt + '}'))
#{'1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}

Answer 2

If you don't want to use literal_eval

str="'1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9"
print({x[0].replace("'", ""):int(x[1]) for x in [y.split(': ') for y in [z for z in str.split(',')]] })
#{'2': 2, '7': 7, '8': 8, '4': 4, '1': 1, '9': 9, '3': 3, '6': 6, '5': 5}