I finished my lab problem, but I have a quick question to fix the end. I have a vector in the function that needs to be returned to main so I can output the elements of the vector. I put return a; at the end of the function since a is the name of the vector in the function but I'm getting an error.
*Where it says "cout << the names are " should be in the main but I can't figure out what to put in the return. *I also put return 0 because it was the only way I had the whole program working since the output is also in the function, but I need it back in main and change the return 0; Sorry if this is a bad question I'm still learning, thanks.
string switching(vector<string> a, int n) {
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
if (a[i] > a[j]) {
swap(a[i], a[j]);
}
}
}
cout << "The order of names are...\n";
for (int i = 0; i < n; i++) {
cout << a[i] << "\n";
}
return 0;
}
As has been suggested, you can change the function signature to
std::vector<std::string> switching(std::vector<std::string> a, int n)
Or, you could pass the string vector argument by reference:
void switching(std::vector<std::string>& a, int n)
This shows a main calling the first version:
#include <iostream>
#include <string>
#include <vector>
std::vector<std::string> switching(std::vector<std::string> a, int n) {
for (int i = 0; i < n - 1; i++) {
for (int j = i + 1; j < n; j++) {
if (a[i] > a[j]) {
swap(a[i], a[j]);
}
}
}
return a;
}
int main()
{
std::vector<std::string> strings{
"John",
"Fred",
"Alice"
};
auto sorted = switching(strings, strings.size());
std::cout << "The order of names are...\n";
for (auto const& name : sorted) {
std::cout << name << "\n";
}
return 0;
}
1.You could modify the return type of the function;
vector<string> switching(vector<string> a, int n)
{
//Your core-code here;
return a;
}
void switching(vector<string> &a, int n)
{
//Your core-code here;
}
In this way, the parameters could change simultaneously in main function.
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