Converting integer to string in Python

Question

尝试my_int.str()会出现错误，指出int没有任何名为str的属性。

Answer 1

>>> str(10)
'10'

>>> int('10')
10

Links to the documentation:

• int()
• str()

Conversion to a string is done with the builtin str() function, which basically calls the __str__() method of its argument.

Answer 2

尝试这个：

str(i)

Answer 3

There is no typecast and no type coercion in Python. You have to convert your variable in an explicit way.

To convert an object into a string you use the str() function. It works with any object that has a method called __str__() defined. In fact

str(a)

is equivalent to

a.__str__()

The same if you want to convert something to int , float , etc.

Answer 4

To manage non-integer inputs:

number = raw_input()
try:
    value = int(number)
except ValueError:
    value = 0

Answer 5

>>> i = 5
>>> print "Hello, world the number is " + i
TypeError: must be str, not int
>>> s = str(i)
>>> print "Hello, world the number is " + s
Hello, world the number is 5

Answer 6

In Python => 3.6 you can use f formatting:

>>> int_value = 10
>>> f'{int_value}'
'10'
>>>

Answer 7

For Python 3.6, you can use the f-strings new feature to convert to string and it's faster compared to str() function. It is used like this:

age = 45
strAge = f'{age}'

Python provides the str() function for that reason.

digit = 10
print(type(digit)) # Will show <class 'int'>
convertedDigit = str(digit)
print(type(convertedDigit)) # Will show <class 'str'>

For a more detailed answer, you can check this article: Converting Python Int to String and Python String to Int

Answer 8

我认为最体面的方式是``。

i = 32   -->    `i` == '32'

Answer 9

You can use %s or .format :

>>> "%s" % 10
'10'
>>>

Or:

>>> '{}'.format(10)
'10'
>>>

Answer 10

For someone who wants to convert int to string in specific digits, the below method is recommended.

month = "{0:04d}".format(localtime[1])

For more details, you can refer to Stack Overflow question Display number with leading zeros .

Answer 11

With the introduction of f-strings in Python 3.6, this will also work:

f'{10}' == '10'

It is actually faster than calling str() , at the cost of readability.

In fact, it's faster than %x string formatting and .format() !

Answer 12

There are several ways to convert an integer to string in python. You can use [ str(integer here) ] function, the f-string [ f'{integer here}'], the .format()function [ '{}'.format(integer here) and even the '%s'% keyword [ '%s'% integer here]. All this method can convert an integer to string.

See below example

#Examples of converting an intger to string

#Using the str() function
number = 1
convert_to_string = str(number)
print(type(convert_to_string)) # output (<class 'str'>)

#Using the f-string
number = 1
convert_to_string = f'{number}'
print(type(convert_to_string)) # output (<class 'str'>)

#Using the  {}'.format() function
number = 1
convert_to_string = '{}'.format(number)
print(type(convert_to_string)) # output (<class 'str'>)

#Using the  '% s '% keyword
number = 1
convert_to_string = '% s '% number
print(type(convert_to_string)) # output (<class 'str'>)

Answer 13

Here is a simpler solution:

one = "1"
print(int(one))

Output console

>>> 1

In the above program, int() is used to convert the string representation of an integer.

Note: A variable in the format of string can be converted into an integer only if the variable is completely composed of numbers.

In the same way, str() is used to convert an integer to string.

number = 123567
a = []
a.append(str(number))
print(a) 

I used a list to print the output to highlight that variable (a) is a string.

Output console

>>> ["123567"]

But to understand the difference how a list stores a string and integer, view the below code first and then the output.

Code

a = "This is a string and next is an integer"
listone=[a, 23]
print(listone)

Output console

>>> ["This is a string and next is an integer", 23]

Answer 14

If you need unary numeral system , you can convert an integer like this:

>> n = 6
>> '1' * n
'111111'

If you need a support of negative ints you can just write like that:

>> n = -6
>> '1' * n if n >= 0 else '-' + '1' * (-n)
'-111111'

Zero is special case which takes an empty string in this case, which is correct.

>> n = 0
>> '1' * n if n >= 0 else '-' + '1' * (-n)
''