Will cout function of c++ stop printing if it comes across a null character(positioned in middle of array) in character array

Question

如果在字符数组中遇到空字符（位于数组中间），c++ 的 cout 函数会停止打印吗？

Answer 1

Firstly, std::cout isn't a function. It's an object (specifically an output stream object).

Its << operator is overloaded. The overloads which are particularly relevant are those which accept strings.

• If we pass a std::string , then << will output every character in the string.

• If we pass a C-style string ( char* ), then << will output every character up to, but not including, the first NUL character encountered. Note that for malformed input (containing no NUL), this can lead to undefined behaviour, due to reading beyond the bounds of the array.

The other (unformatted) output operation is write() , which accepts a character array and a length. That outputs exactly the number of characters specified, including any NULs encountered.