I am trying to get a File-ID from a text file . In the above example the filename is d735023ds1.htm
which I want to get in order to build another url. Those filenames differ however in their length and I would need a universal regex expression to cover all possibilities.
d804478ds1a.htm.
d618448ds1a.htm.
d618448.htm
for cik in leftover_cik_list:
r = requests.get(filing.url)
content = str(r.content)
fileID = None
for line in content.split("\n"):
if fileID == None:
fileIDIndex = line.find("<FILENAME>")
if fileIDIndex != -1:
trimmedText = line[fileIDIndex:]
result = RegEx.search(r"^[\w\d.htm]*$", trimmedText)
if result:
fileID = result.group()
print ("fileID",fileID)
document_link = "https://www.sec.gov/Archives/edgar/data/{0}/{1}/{2}.htm".format(cik, accession_number, fileID)
print ("Document Link to S-1:", document_link)
import re
...
result = re.search('^d\d{1,6}.+\.htm$', trimmedText)
if result:
fileID = result.group()
^d = Start with ad
\\d{1,6} = Look for 1-6 digits, if there could be an unlimited amount of digits replace with \\d{1,}
.+ = Wild card
\\.htm$ = End in .htm
You should try re.match()
which searches for a pattern at the beginning of the input string. Also, your regex is not good, you have to add an anti-shash before .
, as point means "any character" in regex.
import re
result = re.match('[\w]+\.htm', trimmedText)
Try this regex:
import re
files = [
"d804478ds1a.htm",
"d618448ds1a.htm",
"d618448.htm"
]
for f in files:
match = re.search(r"d\w+\.htm", f)
print(match.group())
d804478ds1a.htm
d618448ds1a.htm
d618448.htm
The assumptions in the above are that the file name starts with a d
, ends with .htm
and contains only letters, digits and underscores.
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