Why do I get a blank output when I try to print ASCII table by array approach in Java?

Question

Writing a program to print the ASCII values of all 256 characters.

    int digit[] = new int[256];
    char array[] = new char[256];

    for(int i=0;i<array.length;i++)
    {
        array[i] = (char) digit[i];
    }
    for(int i=0;i<array.length;i++)
    {
        System.out.println(array[i]);
    }

I get a blank output when I run this code.

Answer 1

You do not need int digit[] . You only need to loop from 0 to 255 and cast each int to a char.

for (int i = 0; i < 256; i++) {
    array[i] = (char) i;
}

Alternatively, you can write a for loop using char .

for (char i = 0; i < 256; i++) {
    System.out.println(i);
}

Answer 2

Since you didn't initialize them, all the elements in digit are 0 , and ASCII 0 is the null character.

TO be honest, you don't need an array there - just iterate over them numbers 0 to 255 and print their cast to char s:

for (int i = 0; i < 256; ++i) {
    System.out.println(i + " -- " + ((char)i)));
}