I have a table called "User" where it has the details or user_id and product_item_code.
ex:
Select * from Users limit 5;
+----+---------+---------------------------+
| id | user_id | product_item_code |
+----+---------+---------------------------+
| 1 | 123 | {556,772,945} |
| 2 | 124 | {556,965,945,990} |
| 3 | 125 | {772, 435, 990, 556} |
| 4 | 126 | {556, 623, 842} |
| 5 | 127 | {842, 990, 556, 623, 745} |
+----+---------+---------------------------+
I want to count these product_item_code 556, 990, 623. How many times it's been repeated.
I am looking for a query to give me an output like below
+-------------------+-------+
| product_item_code | count |
+-------------------+-------+
| 556 | 5 |
| 990 | 3 |
| 623 | 2 |
+-------------------+-------+
I have tried the below code but couldn't get the expected output.
select count(1) from Users where ARRAY[556, 990, 623] @> ANY(product_item_code);
Please let me know how can I get the above output. Thanks in advance
You can use unnest
array values and then count them, like:
select u, count(*) from users
join lateral unnest(product_item_code) u on true
where
u in(556, 990, 623)
group by u
order by count(*) desc
No need to unnest. Assuming that a given item never appears twice in a given array, you can enumerate the values in a derived table, join with any()
, and aggregate:
select p.code, count(*) cnt
from (values (556), (990), (223)) p(code)
inner join users u on p.code = any(u.product_item_code)
group by p.code
Use unnest
to turn the arrays into rows and then group by product_item_code
to get your counts:
=# with expand as (
select unnest(product_item_code) as product_item_code
from users
)
select product_item_code, count(*)
from expand
where product_item_code in (556, 990, 623)
group by product_item_code
order by count(*) desc;
product_item_code | count
-------------------+-------
556 | 5
990 | 3
623 | 2
(3 rows)
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