I'm using C++98, I have a vector
with the elements 13
m
1.5
0.6
and I would like to paste them into this string accordingly.
The length of Object 1 is %d%s, weight is %dkg, friction coefficient = %f.
The output will be
The length of Object 1 is 13m, weight is 1.5kg, friction coefficient = 0.6.
I tried it in a for loop but I'm not sure how to update the string after paste the 1st element. Any idea on this?
Thanks for help.
Edited:
The vector
and str
are just example. While, the number of element in vector
will always be the same as the number of delimiter (%d, %s, %f) in the str
.
#include <iostream>
#include <vector>
using namespace std;
int main()
{
vector<string> values;
values.push_back("13");
values.push_back("m");
values.push_back("1.5");
values.push_back("0.6");
string str = "The length of Object 1 is %d%s, weight is %dkg, friction coefficient = %f.";
string str2 = "%d";
string str_crop;
string unk;
string final;
size_t found = str.find(str2);
if (found != std::string::npos)
{
str_crop = str.substr(0, found);
}
for (int i = 0; i < values.size(); i++) {
unk = values[i];
str_crop += unk;
}
final = str_crop;
cout << final << endl;
return 0;
}
I think I understood what you meant to do, I'd say you could use printf but since you want to use cout
I suggest using a logic somewhat like this:
#include <iostream>
#include <vector>
#include <string> //included string for find, length and replace
using namespace std;
int main()
{
vector<string> values;
values.push_back("13");
values.push_back("m");
values.push_back("1.5");
values.push_back("0.6");
string str = "The length of Object 1 is %v%v, weight is %vkg, friction coefficient = %v.";
string str2 = "%v"; //i have swapped the "%d" to make it a "%v", representating value, to make it not too similar to C
string final;
int valloc = 1; //if you ever decide to add more values to that vector
for (int i=0;i<4;i++) {
int oc = str.find(str2);
if (oc < str.length()+1 && oc > -1) {
final=str.replace(oc,2,values[i+(valloc-1)]);
}
}
std::cout << final;
return 0;
}
Explaining what it does is:
1- takes a string
2- finds every occurance of the string's %v
to replace
3- replaces it with the proper value from the vector
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