I am saving a list of strings to save to shared preferences but as I must save the list as a string, I am really struggling to split the string back into the list. My Strings:
"Wellington, NZ"
"Sydney, AU"
"Melbourne, AU"
I save this in shared preferences as "Wellington, NZ, Sydney, AU, Melbourne AU"
How can i split the string back to a list? I cant use string.split(",") as it'll split at every ","
and I have also tried using regex bug have had no luck.
given my string in shared preferences is:
val stringToSplit = "Wellington, NZ, Sydney, AU, Melbourne AU"
I need to split this back into a list that looks like this:
val listOfPlaces = ["Wellington, NZ",
"Sydney, AU",
"Melbourne, AU"]
I think the easiest way would be to append a new string that combines the previous ie:
string1= "Washington, WA"
string2= "Alaska, AK"
string3= "Montana, MT"
string4 = []
string4.append(string1)
string4.append(string2)
string4.append(string3)
print(string4)
which prints:
['Washington, WA', 'Alaska, AK', 'Montana, MT']
You could split them first too if you need the city and state as their own elements.
Please try this:
val s = "a,b,c,d,e"
List<String> myList = new ArrayList<String>(Arrays.asList(s.split(",")))
you will get the list of string
You can use chuncked
with split
to achieve that
val stringToSplit = "Wellington, NZ, Sydney, AU, Melbourne AU"
val splits = stringToSplit.split(",")
val result = splits.chunked(splits.size / 2).map { it.joinToString(",") }
result.forEach { print(it) }
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