I want to write a function which prints the items in a list that all contain at least one similar character and the amount of times it appears in each item. For example if I had the following list:
ex = ['bat', 'cat', 'task', 'tank', 'tan']
Each item contains the letter 'a' and 't' at least once.
I know I could use
for string in ex:
for letter in string:
x = string.count("a")
print(string, "has", x, "a")
for string in ex:
for letter in string:
x = string.count("t")
print(word, "has", x, "t")
How would I do this without specifying the actual characters to search for like above, in case I would like to change the list?
using dictionary
example = ['bat', 'cat', 'task', 'tank', 'tan']
d = {}
for val in example:
for element in val:
if element in d.keys():
d[element] = d[element] + 1
else:
d[element] = 1
print(d)
output
{'b': 1, 'a': 5, 't': 5, 'c': 1, 's': 1, 'k': 2, 'n': 2}
Here is a simple code:)
from functools import reduce
ex = ["bat", "cat", "task", "tank", "tan"]
reduce(lambda a,b: a.intersection(b) ,[set(e) for e in ex])
If you convert each word to a set of characters with [set(x) for x in ex]
, you can use set.intersection()
to return a set of characters that all the words have in common. Then for every letter, you can repeat your code.
ex = ['bat', 'cat', 'task', 'tank', 'tan']
common_letters = set.intersection(*[set(x) for x in ex])
for letter in common_letters:
for string in ex:
x = string.count(letter)
print(string, "has", x, letter)
You could do this ( json
library is only used here for pretty print)
import json
arr = ['bat', 'cat', 'task', 'tank', 'tan']
letters = set(''.join(arr))
d = {}
for letter in letters:
d[letter] = {'words' : [], 'counts' : []}
for letter in letters:
for word in arr:
if letter in word:
d[letter]['words'].append(word)
d[letter]['counts'].append(word.count(letter))
pretty = json.dumps(d, indent=4)
print(pretty)
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