I have a column called 'created_at' in dataframe df, its value is like '2/3/15 2:00' in UTC. Now I want to convert it to unix time, how can I do that?
I tried the script like:
time.mktime(datetime.datetime.strptime(df['created_at'], "%m/%d/%Y, %H:%MM").timetuple())
It returns error I guess the tricky part is the year is '15' instead of '2015'
Is there any efficient way that I am able to deal with it?
Thanks!
%Y
is for 4-digit years.
Since you have 2-digits years (assuming it's 20##), you can use %y
specifier instead (notice the lower-case y).
You should use lowercase %y
(year without century) rather than uppercase %Y
(year with century)
since you mention that you're working with a pandas DataFrame, you can simplify to using
import pandas as pd
import numpy as np
df = pd.DataFrame({'times': ['2/3/15 2:00']})
# to datetime, format is inferred correctly
df['datetime'] = pd.to_datetime(df['times'])
# df['datetime']
# 0 2015-02-03 02:00:00
# Name: datetime, dtype: datetime64[ns]
# to Unix time / seconds since 1970-1-1 Z
# .astype(np.int64) on datetime Series gives you nanoseconds, so divide by 1e9 to get seconds
df['unix'] = df['datetime'].astype(np.int64) / 1e9
# df['unix']
# 0 1.422929e+09
# Name: unix, dtype: float64
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