I have a really simple program that converts a hex string to it's int value. The code seems fine, but it throws a runtime error:
terminate called after throwing an instance of 'std::out_of_range' what(): stoi
Here is the code where the error is being caused:
int dump[4];
string hexCodes[4] = {"fffc0000", "ff0cd044", "ff0000fc", "ff000000"};
for (int i = 0; i < 4; i++)
{
dump[i] = 0;
dump[i] = stoi(hexCodes[i], 0, 16);
cout << dump[i] << endl;
}
I have tried reading a couple of pages such as this . I still can't find anything that relates to my issue. What am I doing wrong that is causing this error?
stoi
will throw out_of_range
if the value is not in the range that int
can represent. The number 0xfffc0000
(4294705152) is not in that range for a 32-bit int
as it is greater than 2^31-1 (2147483647). So throwing the exception is precisely what it must do.
unsigned
would work, but there is no stou
, so use stoul
. You then probably want to use unsigned dump[4]
since you know the value can be represented by an unsigned int
. (Again, as long as they are 32 bits on your system. uint32_t
might be safer.) As a bonus, this will ensure that cout << dump[i]
prints out 4294705152
as desired.
(If you switch to stoul
but keep dump
as an array of int
, the value will be converted to int
by the assignment. Under C++20, and for most common systems under earlier C++ standards, the conversion will "wrap around" to -262144
, and outputting dump[i]
with <<
will print it out just that way, as a signed integer with a minus sign. So that doesn't seem to be what you want.)
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