Counting letters and numbers of list

Question

I'm trying to count the numbers of letters and numbers of a list. For example I want to get 15 letters and 5 numbers. I have a problem because I got the result but when i use debugger I see that for 5 function skips option with isdigit() and goes to isaplha(). What is the reason of this? The second problem is that I got for example 2 numbers as a ten but i want to get only 1. How to rebuild this code?

def coutning(list):
    a= 0
    b = 0
    for elem in list:
        for symbol in elem:
            if elem.isdigit():
                a+=1
            if symbol.isalpha():
                b+=1
    return f' There is {a} numbers and {b} letters'
print(coutning(["1","7","8","9","10", "Hello my 543 friends"]))

Answer 1

You need to move the if elem.isdigit(): condition before the second loop, and put the second loop in else: . Thus, you first check if the element is displaying a number, and if not, then you count the letters in it.

def coutning(list):
    a = 0
    b = 0
    for elem in list:
        if elem.isdigit():
            a += 1
        else:
            for symbol in elem:
                if symbol.isalpha():
                    b += 1
    return f' There is {a} numbers and {b} letters'


print(coutning(["1", "7", "8", "9", "10", "Hello my 543 friends"]))

Prints:

There is 5 numbers and 14 letters

If you want to count all numbers and letters as symbols, you can do it so:

def coutning(list):
    a,b = 0,0
    for elem in ''.join(list):
        a += elem.isdigit()
        b += elem.isalpha()
    return f' There is {a} numbers and {b} letters'

print(coutning(["1", "7", "8", "9", "10", "Hello my 543 friends"]))

Output:

There is 9 numbers and 14 letters

Answer 2

For everyone, I'm so sorry that you didn't understand what I mean. I said that in this code everything is okay until I reach numbers ( 543). When I reach it, I saw in debugger that I got 5, but the code skips isdigit and goes to isalpha. I think that 5 is not alpha, but it works in this way.

def coutning(list):
    a= 0
    b = 0
    for elem in list:
        for symbol in elem:
            if elem.isdigit():
                a+=1
            if symbol.isalpha():
                b+=1
    return f' There is {a} numbers and {b} letters'
print(coutning(["1","7","8","9","10", "Hello my 543 friends"]))