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Collections.sort(list) and list.sort(Comparator.naturalOrder()) in term of performance?

原文 2022-01-07 00:45:16 5 1 java/ list/ performance/ sorting

my question is about the kind of the List that I have to sort it and its order optimisation in both of these sorters in java? which one and when I have to use?

1 answers

The two methods end up executing the same code; there is zero difference between the two.

Collections.sort predates list.sort . That is because list.sort is a so-called default interface method , which is a Java feature that did not exist back then. Hence why Collections.sort exists.

Now that default methods for interfaces is available, list.sort also exists, because java is OOP and 'thingYouWantToDoSomethingWith.theThingYouWantToDo' is better style.

You should use list.sort(Comparator.naturalOrder()) for that reason. Purely style points - there is no difference in effect or performance whatsoever.

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Collections.sort(list) and list.sort(Comparator.naturalOrder()) in term of performance?

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solution1 5 2022-01-07 00:46:38

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5 2022-01-07 00:46:38