How to create an array of 100 integers where every element of array is its index in c language

Question

I want to assign every array with its index and this is my code.

#include <stdio.h>
#include <cs50.h>

int main(void) {
    int length = get_int("How many arrys do you need? ");
    int s[length];
    for (int i = 0; i < length; i++) {
        s[i] = i;
        printf("s[i] = %d\n", i);
    }
 }

when run

s[i] = 0
s[i] = 1

so I want replace i in the code with its index number like this:

s[0] = 0 
s[1] = 1

Answer 1

Your code is fine regarding the initialization of the array.

The printf statement should be changed to print both the index and the value stored at the index:

    printf("s[%d] = %d\n", i, s[i]);

Here is a modified version:

#include <cs50.h>
#include <stdio.h>

int main() {
    int length = get_int("How many array elements do you need? ");
    if (length <= 0 || length > 1024) {
        printf("invalid length: %d\n", length);
        return 1;
    }
    int s[length];
    for (int i = 0; i < length; i++) {
        s[i] = i;
        printf("s[%d] = %d\n", i, s[i]);
    }
    return 0;
}