I am trying to remove elements from String A using an array of String B. My logic is to convert the string A to an array and then check if A contains the same elements as B and write that data to an empty String, but it doesn't work if B has two or more elements. Can you tell me what I'm doing wrong?
class Test {
public static void main(String[] args) {
WordDeleter wordDeleter = new WordDeleter();
// Hello
System.out.println(wordDeleter.remove("Hello Java", new String[] { "Java" }));
// The Athens in
System.out.println(wordDeleter.remove("The Athens is in Greece", new String[] { "is", "Greece" }));
// This cat
System.out.println(wordDeleter.remove("This is cat", new String[] { "is" }));
}
}
class WordDeleter {
public String remove(String phrase, String[] words) {
String[] arrayPhrase = phrase.split(" ");
String result = "";
for (int i = 0; i < arrayPhrase.length; i++) {
for (int j = 0; j < words.length; j++) {
if (!arrayPhrase[i].equalsIgnoreCase(words[j]))
result += arrayPhrase[i] + " ";
}
}
return result.trim();
}
}
Output is:
Hello
The The Athens Athens is in in Greece
This cat
You're close but you need to use the helpful .contains()
method. This should work for the multi-length set of words. Your nested for loop
checked for both words, thus the copying. Also the not-allowed words were only written once, so it infact "worked" but not the way you intended.
class Test {
public static void main(String[] args) {
WordDeleter wordDeleter = new WordDeleter();
// Hello
System.out.println(wordDeleter.remove("Hello Java", new String[] { "Java" }));
// The Athens in
System.out.println(wordDeleter.remove("The Athens is in Greece", new String[] { "is", "Greece" }));
// This cat
System.out.println(wordDeleter.remove("This is cat", new String[] { "is" }));
}
}
class WordDeleter {
public String remove(String phrase, String[] words) {
String[] arrayPhrase = phrase.split(" ");
String result = "";
for (int i = 0; i < arrayPhrase.length; i++) {
// If the word is not contained in the not allowed array
if(!words.contains(arrayPhrase[i])){
result += arrayPhrase[i] + " ";
}
}
return result.trim();
}
}
Another thing you can do to make it better is use StringBuilder
. Instead of String result = ""
, use StringBuilder result = new StringBuilder()
. And instead of result +=arrayPhrase[i] + " ";
use result.append(arrayPhrase[i] + " ");
as so:
class Test {
public static void main(String[] args) {
WordDeleter wordDeleter = new WordDeleter();
// Hello
System.out.println(wordDeleter.remove("Hello Java", new String[] { "Java" }));
// The Athens in
System.out.println(wordDeleter.remove("The Athens is in Greece", new String[] { "is", "Greece" }));
// This cat
System.out.println(wordDeleter.remove("This is cat", new String[] { "is" }));
}
}
class WordDeleter {
public String remove(String phrase, String[] words) {
String[] arrayPhrase = phrase.split(" ");
StringBuilder result = new StringBuilder();
for (int i = 0; i < arrayPhrase.length; i++) {
// If the word is not contained in the not allowed array
if(!words.contains(arrayPhrase[i])){
result.append(arrayPhrase[i] + " ");
}
}
return result.toString().trim();
}
}
The most efficient way to remove all occurrences of strings contained in the given array from the given string is to generate a HashSet
from the given array and check for every word in the given string , whether it's present in the set or not.
To avoid overheads of string concatenation, we can use StringJoiner
.
That's how it can be implemented.
public static String remove(String phrase, String[] words) {
String[] arrayPhrase = phrase.split(" ");
Set<String> wordsToRemove = Arrays.stream(words).collect(Collectors.toSet());
StringJoiner result = new StringJoiner(" ");
for (String word: arrayPhrase) {
if (!wordsToRemove.contains(word)) {
result.add(word);
}
}
return result.toString();
}
And that's how it can be implemented with streams using collector joining()
:
public static String remove(String phrase, String[] words) {
Set<String> wordsToRemove = Arrays.stream(words).collect(Collectors.toSet());
return Arrays.stream(phrase.split(" "))
.filter(word -> !wordsToRemove.contains(word))
.collect(Collectors.joining(" "));
}
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