How to convert a String into an array of Strings containing one character each

Question

I have a small problem here.I need to convert a string read from console into each character of string. For example string: "aabbab" I want to this string into array of string.How would I do that?

Answer 1

String[] result = input.split("(?!^)");

这样做是将输入字符串拆分为所有未以字符串开头开头的空字符串。

Answer 2

String x = "stackoverflow";
String [] y = x.split("");

Answer 3

If by array of String you mean array of char:

public class Test
{
    public static void main(String[] args)
    {
        String test = "aabbab ";
        char[] t = test.toCharArray();

        for(char c : t)
            System.out.println(c);    

        System.out.println("The end!");    
    }
}  

If not, the String.split() function could transform a String into an array of String

See those String.split examples

/* String to split. */
String str = "one-two-three";
String[] temp;

/* delimiter */
String delimiter = "-";
/* given string will be split by the argument delimiter provided. */
temp = str.split(delimiter);
/* print substrings */
for(int i =0; i < temp.length ; i++)
  System.out.println(temp[i]);

The input.split("(?!^)") proposed by Joachim in his answer is based on:

• a ' ?! ' zero-width negative lookahead (see Lookaround )
• the caret ' ^ ' as an Anchor to match the start of the string the regex pattern is applied to

Any character which is not the first will be split. An empty string will not be split but return an empty array.

Answer 4

You mean you want to do "aabbab".toCharArray(); ? Which will return an array of chars. Or do you actually want the resulting array to contain single character string objects?

Answer 5

You can use String.split(String regex):

String input = "aabbab";
String[] parts = input.split("(?!^)");

Answer 6

Use toCharArray() method. It splits the string into an array of characters:

http://java.sun.com/j2se/1.5.0/docs/api/java/lang/String.html#toCharArray%28%29

String str = "aabbab";
char[] chs = str.toCharArray();