Storing and printing 10+ digit integer in c++

Question

I'm using cout to print digits to the console. I am also storing values of up to 13+billion as a digit and doing computations on it. What data type should I use?

When I do the following:

int a = 6800000000;
cout << a;

It prints -1789934592.

thanks.

Answer 1

long long最多可以容纳 9223372036854775807。如果需要更大的，请使用gmp东西。

Answer 2

Use int64_t to guarantee you won't overflow. It is available from stdint.h .

Answer 3

Just a note that both int64_t and long long are included in C99 and in C++ 0x, but not in the current version of C++. As such, using either does put your code at some risk of being non-portable. Realistically, however, that risk is probably already pretty low -- to the point that when/if you port your code, there are likely to be much bigger problems.

If, however, you really want to assure against that possibility, you might consider using a double precision floating point. Contrary to popular belief, floating point types can represent integers exactly up to a certain limit -- that limit being set (in essence) by the size of the mantissa in the FP type. The typical implementation of a double has a 53-bit mantissa, so you can represent 53-bit integers with absolute precision. That supports numbers up to 9,007,199,254,740,992 (which is substantially more than 13 of either of the popular meanings of "billion").

Answer 4

Your data type (int) is too small to hold such large numbers. You should use a larger data type or one of the fixed size data types as given in the other answer (though you should really use uint64_t if you're not using negative numbers).

Answer 5

It's a good idea to understand the range limits of different sized types.

A 32 bit type (on most 32 bit platforms, both int and long are 32 bit) have the following ranges:

signed: -2,147,483,648 to 2,147,483,647
unsigned: 0 to 4,294,967,295

While 64 bit types (typically long long's are 64 bit, on most Unix 64 bit platforms a long is also 64) have the following range:

signed: -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807
unsigned: 0 to 18,446,744,073,709,551,615

Answer 6

只需在声明语句中使用 double

Answer 7

unsigned long long

can be used

Answer 8

You could use a long int:

long int a

Or if it's always going to be positive, an unsigned long int:

unsigned long int a

See: http://forums.guru3d.com/showthread.php?t=131678