Convert mathematical string to int

Question

是否有一种简单的方法来取一个字符串，如“5 * 4”并返回20？

Answer 1

The most simple way would be to use the Rhino JavaScript engine available with the JRE 6 standard API.

Edit: as per the comments, if the strings are user-supplied, this could be a potential security hole. Be sure to filter out everything except digits, braces and mathematical operators.

Answer 2

你可能正在寻找像JbcParser - Math Parser for Java这样的东西。

Answer 3

I don't know which are the best out there but there are "mathematical expressions evaluator" packages.

check out Java Math Expression Evaluator ( one file source code included)

Example use from site:

java -cp meval.jar com.primalworld.math.MathEvaluator -cos(0)*(1+2)
java -cp meval.jar com.primalworld.math.MathEvaluator .05*200+3.01

Answer 4

More details about expression evaluation can be found at:

Algorithms in Java, Volume 1, Parts 1-4

Answer 5

I have googled a bit and found that one here . Its not exactly what you need, but maybe it helps depsite of that.

import javax.script.ScriptEngine;
import javax.script.ScriptEngineManager;
import javax.script.ScriptException;

public class ScriptDemo {

    public static void main(String[] args) {

        ScriptEngineManager manager = new ScriptEngineManager();
        ScriptEngine engine = manager.getEngineByName("js");

        engine.put("a", 1);
        engine.put("b", 2);

        try {
            String expression = "(a + b) > 2";
            Object result = engine.eval(expression);
            System.out.println(expression+" ? "+result);
        } catch(ScriptException se) {
            se.printStackTrace();
        }
    }
}

Answer 6

Sounds like you should check out JEXL (Java Expression Language)

It is very easy to use ; for example, the solution to your problem is:

  public static void main(String[] args) {
    long a = 5;
    long b = 4;
    String theExpression = "a * b";
    JexlEngine jexl = new JexlEngine();
    Expression e = jexl.createExpression(theExpression);
    JexlContext context = new MapContext();
    context.set("a", a);
    context.set("b", b);
    Long result = (Long) e.evaluate(context);
    System.out.println("The answer : " + result);
  }

Alternatively you could use the following if the string is read in directly:

 public static void main(String[] args) {
   JexlEngine jexl = new JexlEngine();
   Expression e = jexl.createExpression("5 * 4");
   Integer result = (Integer) e.evaluate(null);
   System.out.println("The answer : " + result);
 }

Answer 7

You are best off using a library for this. Janino has the ability to evaluate arbitrary Java expressions like the ones you specify, and more besides.

Check out the ExpressionEvaluator example.

Answer 8

You could try parsing it yourself by using Integer.parseInt() and using a switch() statement to find the operators.

You could also try using javax.script.ScriptEngine; for more information see http://forums.sun.com/thread.jspa?threadID=5144807 .

Answer 9

You can also use BeanShell .
It is actually more a Java source interpreter, but recently I used it to evaluate some expressions containing variables (only the eval method is using BeanShell, the rest is for preparing the output):

import bsh.EvalError;
import bsh.Interpreter;

public class EVAL {

    private static final String FORMAT = "%-5s | %-5s | %-5s | %s%n";

    public static void main(String[] args) {
        tabela("((a && b)||c)");
        tabela("a ? (b || c) : (b && c)");
        tabela("(a?1:0) + (b?1:0) + (c?1:0) >= 2");
    }

    private static void tabela(String expressao) {
        System.out.printf(FORMAT, "  a  ", "  b  ", "  c  ", expressao);
        System.out.printf(FORMAT, "-----", "-----", "-----", expressao.replaceAll(".", "-"));
        try {
            for (int i = 0; i < 8; i++) {
                boolean a = (i & (1<<2)) != 0;
                boolean b = (i & (1<<1)) != 0;
                boolean c = (i & (1<<0)) != 0;
                boolean r = eval(expressao, a, b, c);
                System.out.printf(FORMAT, a, b, c, r);
            }
        } catch (EvalError ex) {
            ex.printStackTrace();
        }
        System.out.println();
        System.out.println();
    }

    private static boolean eval(String expressao, boolean a, boolean b, boolean c) throws EvalError {
        Interpreter inter = new Interpreter();
        inter.set("a", a);
        inter.set("b", b);
        inter.set("c", c);
        Object resultado = inter.eval(expressao);
        return (Boolean) resultado;
    }
}

results:

  a   |   b   |   c   | ((a && b)||c)
----- | ----- | ----- | -------------
false | false | false | false
false | false | true  | true
false | true  | false | false
false | true  | true  | true
true  | false | false | false
true  | false | true  | true
true  | true  | false | true
true  | true  | true  | true


  a   |   b   |   c   | a ? (b || c) : (b && c)
----- | ----- | ----- | -----------------------
false | false | false | false
false | false | true  | false
false | true  | false | false
false | true  | true  | true
true  | false | false | false
true  | false | true  | true
true  | true  | false | true
true  | true  | true  | true


  a   |   b   |   c   | (a?1:0) + (b?1:0) + (c?1:0) >= 2
----- | ----- | ----- | --------------------------------
false | false | false | false
false | false | true  | false
false | true  | false | false
false | true  | true  | true
true  | false | false | false
true  | false | true  | true
true  | true  | false | true
true  | true  | true  | true

Answer 10

I have used JEval in the past and have found it quite easy and intuitive. Here is a code snippet:

import net.sourceforge.jeval.EvaluationException;
import net.sourceforge.jeval.Evaluator;

public class Main {
    public static void main(String[] args) {
        try {
            System.out.println(new Evaluator().evaluate("5+4*3"));
        }
        catch (EvaluationException e) {
            e.printStackTrace();
        }
    }
}

Answer 11

There is also this one:

https://eval.dev.java.net/