Linux cp with a regexp

Question

I would like to copy some files in a directory, renaming the files but conserving extension. Is this possible with a simple cp , using regex ?

For example :

cp ^myfile\.(.*) mydir/newname.$1

So I could copy the file conserving the extension but renaming it. Is there a way to get matched elements in the cp regex to use it in the command ? If not, I'll do a perl script I think, or if you have another way...

Thanks

Answer 1

Suppose you have myfile.a , myfile.b , myfile.c :

for i in myfile.*; do echo mv "$i" "${i/myfile./newname.}"; done

This creates (upon removal of echo ) newname.a , newname.b , newname.c .

Answer 2

The shell doesn't understand general regexes; you'll have to outsource to auxiliary programs for that. The classical scripty way to solve your task would be something like

for a in myfile.* ; do
  b=`echo $a | sed 's!^myfile!mydir/newname!'`
  cp $a $b
done

Or have a perl script generate a list of commands that you then source into the shell.

Answer 3

I really like the regex syntax of the rename perl script (by Robin Barker and Larry Wall), eg:

rename "s/OldFile/NewFile/" OldFile*

OldFile.c and OldFile.h are renamed to NewFile.c and NewFile.h , respectively

I simply wanted the exact same thing with a copy command:

copy "s/OldFile/NewFile/" OldFile*

So I duplicated that script and changed the rename statement to copy via File::Copy . Et voila! A copy command with perl-regex syntax:

https://gist.github.com/jcward/0ead33bd79f2061c68728cc82582241f