Match a pipe character in the middle of a string with a python regex

Question

I am trying to match a pipe character in a string using a Python regex and I can't seem to get it to match. I've boiled it down to a simplified version.

Let's say I am looking for the sequence z|a in a string. Here are some possible regexes and the results:

>>> import re
>>> re.match(r'|', 'xyz|abc')
<_sre.SRE_Match object at 0x2d9a850>
>>> re.match(r'z|', 'xyz|abc')
<_sre.SRE_Match object at 0x2d9a780>
>>> re.match(r'|a', 'xyz|abc')
<_sre.SRE_Match object at 0x2d9a850>
>>> re.match(r'z|a', 'xyz|abc')
>>> re.match(r'z\|a', 'xyz|abc')
>>> re.match(r'z\\|a', 'xyz|abc')
>>> re.match(r'z\\\|a', 'xyz|abc')
>>> re.match(r'z[|]a', 'xyz|abc')
>>> 

So I can match with | , |a and z| but I can't find a way to match z|a . Any ideas?

Answer 1

re.match() is looking for a match at the start of the string. Use re.search() instead.

The patterns you have that match are matching the empty string. ie r'|' is empty string or empty string, r'z|' is z or empty string and '|a' is empty string or a. all of those will match on any string.

>>> re.match('z\\|a', 'xyz|abc')
>>> re.search('z\\|a', 'xyz|abc')
<_sre.SRE_Match object at 0x02BF2BB8>
>>> re.search(r'z\|a', 'xyz|abc')
<_sre.SRE_Match object at 0x02BF2BF0>

More generally you can use re.escape() on a literal string that you need to include in the middle of a more complex regular expression to avoid having to figure out how many backslashes you need to unescape things.

Answer 2

You can use the following method to get re.match to match middle of the string.

myPattern = "how"

re.match('(.)*(%s)' %myPattern, 'Hello, how are you ?')*

The . matches anything in regex. Basically, you are asking for match to skip any number of characters needed to match your pattern.