Wanted to convert
<br/>
<br/>
<br/>
<br/>
<br/>
into
<br/>
You can do this with a regular expression:
preg_replace("/(<br\s*\/?>\s*)+/", "<br/>", $input);
This if you pass in your source HTML, this will return a string with a single <br/> replacing every run of them.
我的几乎与levik的(+1)相同,只是考虑了一些不同的br格式:
preg_replace('/(<br[^>]*>\s*){2,}/', '<br/>', $sInput);
较短的增强的可读性,无论属性如何,都能产生正确的输出:
preg_replace('{(<br[^>]*>\s*)+}', '<br/>', $input);
Thanks all.. Used Jakemcgraw's (+1) version
Just added the case insensative option..
{(<br[^>]*>\s*)+}i
Great tool to test those Regular expressions is:
使用正则表达式匹配<br/>
一次或多次,然后使用preg_replace(或类似的内容)替换为<br/>
例如levik的回复。
without preg_replace, but works only in PHP 5.0.0+
$a = '<br /><br /><br /><br /><br />';
while(($a = str_ireplace('<br /><br />', '<br />', $a, $count)) && $count > 0)
{}
// $a becomes '<br />'
You probably want to use a Regular Expression. I haven't tested the following, but I believe it's right.
$text = preg_replace( "/(<br\s?\/?>)+/i","<br />", $text );
A fast, non regular-expression approach:
while(strstr($input, "<br/><br/>"))
{
$input = str_replace("<br/><br/>", "<br/>", $input);
}
User may enter many variants
<br>
<br/>
< br />
<br >
<BR>
<BR>< br>
...and more.
So I think it will be better next
$str = preg_replace('/(<[^>]*?br[^>]*?>\s*){2,}/i', '<br>', $str);
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