I have the following table:
column_a column_b column_c column_d column_date
1 test_1 test_1 type_1 11:00
2 test_2 test_2 type_2 11:01
3 test_3 test_6 type_2 11:02
4 test_4 test_4 type_3 11:03
5 test_2 test_6 type_2 11:04
6 test_1 test_2 type_1 11:05
I have to check which row has another value in column_b and column_c filtered by the column_d (type). I must analyze with my sql script only the first two rows ordered by column_date for each type. If there is a difference between the two rows in one of the columns (column_b, column_c or column_d), I have to print out the value of the first row (otherwise null).
In example above I expect the following result:
column_a column_b column_c column_d column_date
5 test_2 null type_2 11:04
6 null test_2 type_1 11:05
I can use T-SQL of the MS SQL Server 2008.
It is not clear for me what datatype you use for column_date column, but let us assume that it is time one.
DECLARE @Table TABLE (
column_a INT ,
column_b VARCHAR (128),
column_c VARCHAR (128),
column_d VARCHAR (128),
column_date [time] );
INSERT INTO @Table
VALUES
('1', 'test_1', 'test_1', 'type_1', '11:00'),
('2', 'test_2', 'test_2', 'type_2', '11:01'),
('3', 'test_3', 'test_6', 'type_2', '11:02'),
('4', 'test_4', 'test_4', 'type_3', '11:03'),
('5', 'test_2', 'test_6', 'type_2', '11:04'),
('6', 'test_1', 'test_2', 'type_1', '11:05');
WITH C
AS (SELECT *,
ROW_NUMBER() OVER (PARTITION BY column_d ORDER BY column_date DESC) AS RN
FROM @Table),
ToCompare
AS (SELECT *
FROM c
WHERE Rn < 3
AND EXISTS (SELECT *
FROM c AS C2
WHERE C.column_d = C2.column_d
AND Rn = 2))
SELECT T.column_a,
NULLIF (T.column_b, T2.column_b) AS [column_b],
NULLIF (T.column_c, T2.column_c) AS [column_c],
T.column_d,
T.column_date
FROM ToCompare AS T
INNER JOIN
ToCompare AS T2
ON T.column_d = T2.column_d
WHERE T.Rn = 1
AND T2.RN = 2
ORDER BY T.column_a;
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