Python Parseing String by Single Quotes

Question

I am trying to Parse the following string:

EDITED to account for spaces...

['THE LOCATION', 'THE NAME', 'THE JOB', 'THE AREA')]

Right now I use regular expressions and split the data with the comma into a list

InfoL = re.split(",", Info)

However my output is

'THE LOCATION'
'THE NAME'
'THE JOB'
'THE AREA')]

Looking to have the output as follows

THE LOCATION
THE NAME
THE JOB
THE AREA

Thoughts?

Answer 1

One possibility is to use strip() to remove the unwanted characters:

In [18]: s="['LOCATION', 'NAME', 'JOB', 'AREA')]"

In [19]: print '\n'.join(tok.strip("[]()' ") for tok in s.split(','))
LOCATION
NAME
JOB
AREA

Like your original solution, this will break if any of strings are allowed to contain commas.

PS If that closing parenthesis in your example is a typo, you might be able to use ast.literal_eval() :

In [22]: print '\n'.join(ast.literal_eval(s))
LOCATION
NAME
JOB
AREA

Answer 2

InfoL = re.split("[, '()\[\]]*", Info)

Answer 3

try this code snippet :

import re
tmpS = "['THE LOCATION', 'THE NAME', 'THE JOB', 'THE AREA')]"
tmpS = re.sub('[^\w\s,]+', '', tmpS)
print tmpS # Result -> 'THE LOCATION, THE NAME, THE JOB, THE AREA'
for s in tmpS.split(','):
     print s.strip()


O/P:
THE LOCATION
THE NAME
THE JOB
THE AREA