Regular expression to replace with empty string

Question

I require a regular expression which does following

1. Match if first alphabet of first word in starting line is in lowercase .
2. Starting from word containing above alphabet , replace with empty string until a word starting with uppercase occurs

This is what I tried:

string result = Regex.Replace(input,@"^[a-z]\s?[a-z0-9]\s?[^A-Z]","");

This is what should happen:

Sample input = "of !jgf area. The wealth of nation"

Required Output ="The Wealth of nation"

What should I do to improve/correct?

Answer 1

您可以像下面这样：

string result = Regex.Replace(input,@"^[^A-Z]*","");

Answer 2

This pattern will suffice.

^[^A-Z]+

It will replace all the characters that is not an upper case letter

By the way there is a much faster way without RegEx in C#.

int index=str.indexOfAny(new char[] { 'A', 'B', ..., 'Z'})
if(index!=-1){
    str = str.Substring(index);
}

Answer 3

" ([A-Z]+.*)"

使用组，Gruops [1]是您想要的