Hi I have a big string like this :
"999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999"
I wish to convert this string to long. But I failed. I did:
Long.parseLong(longString);
But I'm getting an error:
java.lang.NumberFormatException: For input string: "99999999.......
Are there any way to avoid this?
像这样使用BigInteger类:
BigInteger number = new BigInteger(longString);
You need to use BigInteger
. Long
may not accommodate that big number.
Here is javadoc for BigInteger .
you might use BigInteger rather than Long.
BigInteger number = new BigInteger(longString);
long: Reference
use 8-byte to store values from -9,223,372,036,854,775,808
to 9,223,372,036,854,775,807
As mention before answer, use BigInteger
.
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