Store a randomly generated integer as a variable in c++

Question

I am working with the pseudo random function srand() to generate a number between a range of two integers (1 and 4).

I include ctime and use a flag controlled while loop to check to see that the numbers will be different each loop.

time_t t;
time(&t);
srand(t);

and then print out the results

cout << "My random number" << (rand()%(1-5))+1 << endl;

I wish to replace (rand()%(1-5))+1 with a variable ex : int myRandomNumber for use in another loop for determining how many objects will be generated later on in my code

How can i assign the desired random value i get to myRandomNumber ?

Thank you for your time,

Answer 1

int myRandomNumber = (rand() % 4) + 1;

Answer 2

Just declare the variable:

int myRandomNumber;

and then assign the value to the variable:

myRandomNumber=(rand()%(1-5))+1;