I'm calling a RESTful Api from my Java application which provides me result in following format:
["Item1", "Item2" , "Item3"]
How do I parse it into ArrayList object?
Code:
private String getResponseString(URI URL) {
HttpClient client = new DefaultHttpClient();
HttpContext context = new BasicHttpContext();
HttpGet get = new HttpGet();
get.setURI(URL);
try {
HttpResponse response = client.execute(get, context);
return getASCIIContentFromEntity(response.getEntity());
} catch (ClientProtocolException e) {
Log.e(Static.DebugTag, e.getMessage());
return null;
} catch (IOException e) {
Log.e(Static.DebugTag, e.getMessage());
return null;
}
}
private String getASCIIContentFromEntity(HttpEntity entity)
throws IllegalStateException, IOException {
InputStream in = entity.getContent();
StringBuffer out = new StringBuffer();
int n = 1;
while (n > 0) {
byte[] b = new byte[4096];
n = in.read(b);
if (n > 0)
out.append(new String(b, 0, n));
}
return out.toString();
}
Now I want to make another function that takes the String returning form getASCIIContentFromEntity() as param and return an Arraylist.
PS I have response in a string object.
PPS Title may be misleading as in I don't have idea what to call it.
Thanking in anticipation.
Since the string appears to contain valid JSON , you could use a JSON parser, such as Gson , to parse the string. See Arrays Examples and Collections Examples in the manual.
抢劫java.util.Arrays。
List<String> list = Arrays.asList(["Item1", "Item2", "Item3"]);
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.