在Python中查找多个重叠矩形的交集区域

Question

我尝试使用此处显示的算法： https ： //discuss.leetcode.com/topic/15733/my-java-solution-sum-of-areas-overlapped-area

然而，该算法仅涉及找到仅两个重叠矩形的区域。

如果我知道每个矩形的长度和宽度，我将如何继续找到3个，4个或5个等重叠矩形的交叉区域？

Answer 1

对于像这样的东西， Shapely是一个很好的库。

from shapely.geometry import box

# make some rectangles (for demonstration purposes and intersect with each other)
rect1 = box(0,0,5,2)
rect2 = box(0.5,0.5,3,3)
rect3 = box(1.5,1.5,4,6)

rect_list = [rect1, rect2, rect3]

# find intersection of rectangles (probably a more elegant way to do this)
for rect in rect_list[1:]:
    rect1 = rect1.intersection(rect)
intersection = rect1

想象一下这里发生了什么。 我绘制矩形及其交点：

from matplotlib import pyplot as plt
from matplotlib.collections import PatchCollection
from matplotlib.patches import Polygon

# plot the rectangles before and after merging 

patches  = PatchCollection([Polygon(a.exterior) for a in rect_list], facecolor='red', linewidth=.5, alpha=.5)
intersect_patch =  PatchCollection([Polygon(intersection.exterior)], facecolor='red', linewidth=.5, alpha=.5)

# make figure
fig, ax = plt.subplots(1,2, subplot_kw=dict(aspect='equal'))
ax[0].add_collection(patches, autolim=True)
ax[0].autoscale_view()
ax[0].set_title('separate polygons')
ax[1].add_collection(intersect_patch, autolim=True)
ax[1].set_title('intersection = single polygon')
ax[1].set_xlim(ax[0].get_xlim())
ax[1].set_ylim(ax[0].get_ylim())
plt.show()