如何在循环中检查准确性？

Question

我正在尝试为我的实验编写一个函数，该函数在中间的彩色矩形上方显示2个标签。 拍摄对象必须按向左或向右按​​上面的标签之一对颜色进行分类。

我想在循环中进行编码，如果准确性为1，则实验应显示一个信息文本，说明他们的选择正确；反之亦然，如果准确性为0，则按回车继续后，应返回到原始循环，然后重复自身。

我怎么做？

# make a function for one trial of colour practice
def con1_trial(self):
    global trial
    global key
    trial += 1
    target_colour = random.choice(colours) 

    # show one square with gouloboy colour in top right corner of screen
    col3rec.setFillColor(target_colour)
    col3rec.draw()
    sinij_text.draw()
    boy_text.draw()

    # draw and flip
    win.flip()

    key, test_answer = event.waitKeys(keyList=['right', 'left', 'escape'], timeStamped = True)[0]
    for colour_pair in colour_pairs:
        if test_colour == colours[0] and key == "left":
            accuracy = 1
        elif test_colour == colours[1] and key == "right":
            accuracy = 1
        elif key == 'escape':
            core.quit() 
        else: accuracy = 0

    # records time in ms
    rt = (test_answer - test_start)*1000
    return accuracy, rt

Answer 1

尝试的定义是选择一种颜色，绘画，等待输入并记录答案。 这是一些伪代码

def trial():
    color = random.choice(colours)
    # draw stuff
    # set time start
    # wait for key press
    # check if key press correct
    # print whether they were correct and the time
    if enter pressed: trial()

Answer 2

为了使代码更简洁，首先在脚本的较早位置定义一个反馈函数：

feedback_text = visual.TextStim(win)
def show_feedback(feedback):
    # Show feedback on screen
    feedback_text.text = feedback
    feedback_text.draw()
    win.flip()

    # Wait for key
    event.waitKeys()

在您的代码之后添加以下内容：

# Show feedback
if accuracy == 1:
    show_feedback('Correct! Well done. Press a key to continue...')
elif accuracy == 0:
    show_feedback('Wrong! Press a key to continue...')

...具有正确的压痕级别。 我总是最终拥有某种显示消息的功能。 在show_feedback您还可以添加一些内容以退出实验：

key = event.waitKeys()[0]  # get first key pressed
if key == 'escape':
    core.quit()