How can I get the value of a JSON field in XSLT?

Question

I would like to fetch the below text via xslt. Input is -

{
   "Contact Id":"3333333333",
   "Contact No":"9811430620",
   "Email Id":"abhishek.jain@homecredit.co.in",
   "Last Name":"Jain","First Name":"Abhishek"
}

Now i need only this text in output : 3333333333 .

Pls do let me know how to do in xslt.

Thanks

Answer 1

Well the input is not XML but JSON it seems so you might need to use an XSLT 3.0 processor like Saxon 9.6 PE or EE and the json-to-xml functionality

<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="3.0">
    <xsl:output method="text" />

    <xsl:template match="json">
        <xsl:value-of select="json-to-xml(.)//*[@key = 'Contact Id']"/>
    </xsl:template>
</xsl:transform>

That assumes that your input actually has the JSON inside of an XML input element <json>{"Contact Id":"3333333333","Contact No":"9811430620","Email Id":"abhishek.jain@homecredit.co.in","Last Name":"Jain","First Name":"Abhishek"}</json> , if not, you would need to use json-to-xml(unparsed-text('file.json'))//*[@key = 'Contact Id'] .

Answer 2

This looks like JSON data. You tagged your question as XSLT 2.0, but if your processor is capable with xslt-3.0 , you can use parse-json() to get a map, or json-to-xml() to apply templates to it.

Other than that, it gets a bit ugly by using regexes, ie something like:

<xsl:value-of select="replace(., '.*Contact Id.:.(\d+).*', '$1')" />