How to extract number from text in python?

Question

I have the string listed below

str = ['"Consumers_Of_Product": {"count": 13115}']

How can I extract the number 13115 as it will change, so that it will always equal var. In other words how do I extract this number from this string?

Most things I've done previously have not worked and I think that is due to the syntax. I'm running Python 2.7.

Answer 1

If you just want to extract that number, provided there are no other numbers in that string, you can use regex . I renamed str to be s for the reason mentioned in @TigerhawkT3 answer.

import re
s = ['"Consumers_Of_Product": {"count": 13115}']
num = re.findall('\d+', s[0])
print(num[0])
13115

Answer 2

Use ast.literal_eval on the single element in that list (which you shouldn't call str because it masks the built-in, and it isn't a string anyway), within curly braces (as it seems to be a dictionary element):

>>> import ast
>>> s = ['"Consumers_Of_Product": {"count": 13115}']
>>> ast.literal_eval('{{{}}}'.format(s[0]))
{'Consumers_Of_Product': {'count': 13115}}

Answer 3

You have 3 options

But it's recommended to use json lib

import json
s = ['"Consumers_Of_Product": {"count": 13115}']
s[0] = '{' + s[0] + '}'
my_var = json.loads(s[0]) # this is where you translate from string to dict
print my_var['Consumers_Of_Product']['count']
# 13115

remembering what TigerhawkT3 said about why you shouldn't use str

Answer 4

You can use regular expression to extract anything you want from a string. Here is a link about HOW TO use Regular expression in python

sample code here:

import re
m = re.search(r'(\d+)', s[0])
if m:
    print m.group()
else:
    print 'nothing found'

Your string looks something like a JSON string, so if you are dealing with json string, you can make use of json package to extract the value for field count

sample code here (you need to wrap your string with {} or array [] ):

import json
obj = json.loads('{"Consumers_Of_Product": {"count": 13115}}')
print(obj['Consumers_Of_Product']['count'])