I have a line of data of 264 bits in memory buffer written using Verilog HDL.
buffer[2]=264'b000100000100001000000000001000000000000001000001000000000000000000000000000000000000100000010000010000100000000000100000000010000100001100000000000000000000000000000000000010000001000001000010000000000010000000000000010001010000000000000000000000000000000000001000;
I want to transfer 10 bits within the above raw from buffer[2][147:138]
bits to buffer[2][59:50]
, then transfer buffer[2][235:226]
bits into buffer[2][147:138]
I try to do this using XOR but it dose not work
buffer[2][59:50]=buffer[2][59:50]^buffer[2][147:138];
buffer[2][147:138]=buffer[2][59:50]^buffer[2][147:138];
buffer[2][59:50]=buffer[2][59:50]^buffer[2][147:138];
buffer[2][235:226]=buffer[2][235:226]^buffer[2][147:138];
buffer[2][147:138]=buffer[2][235:226]^buffer[2][147:138];
buffer[2][235:226]=buffer[2][235:226]^buffer[2][147:138];
How can I do this without using non-blocking assignment ?
Just create a new variable to hold the new, rearranged, array. This should not generate any logic, you are just rearranging wires.
reg [263:0] reArrBuffer [0:2];
assign reArrBuffer =
'{buffer[0],
buffer[1],
{buffer[2][263:148], buffer[2][235:226], buffer[2][137:60], buffer[2][147:138], buffer[2][49:0]}
};
Note: You need '
in front of the first {
to create an assignment pattern for an unpacked array. It can be removed if buffer
and reArrBuffer
is packed.
You can swap with concatenations, no xor required:
{buffer[2][147:138],buffer[2][59:50]} = {buffer[2][59:50],buffer[2][147:138]};
{buffer[2][235:226],buffer[2][147:138] = {buffer[2][147:138],buffer[2][235:226]};
Your title says swap , but your description says transfer . To transfer you can can still use the same approach:
{buffer[2][147:138],buffer[2][59:50]} = {buffer[2][235:226],buffer[2][147:138]}
// Or you can do this, beware order matters
buffer[2][59:50] = buffer[2][147:138];
buffer[2][147:138] = buffer[2][235:226];
Be careful where you do this in an always
block. It can create a combinational feedback loop after synthesized if done incorrectly. The bits must first be assigned by a determinate value (ideally a flop) before doing the swap.
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