I'm looking for an existing solution, for converting a number with a metric prefix (SI style) to float or int.
Additionally, my initial number with a metric prefix is a string .
Example:
I have:
a = "1u"
b = "2m"
c = "1.1u"
I want:
a = 0.000001
b = 0.002
c = 0.0000011
Use the QuantiPhy package. It is a stable well documented and well supported package that is designed to do just what you want.
>>> from quantiphy import Quantity
>>> all = dict(
... a = Quantity('1u'),
... b = Quantity('2m'),
... c = Quantity('1.1u)'
... )
>>> for n, v in all.items():
... print(f'{n} = {v:<0.7f}')
a = 0.000001
b = 0.002
c = 0.0000011
Quantity subclasses float, so a quantity can be used anywhere a float can be used.
>>> print(sum(all.values()))
0.0020021
When printing it you can retain the SI scale factors. You can also add units to make the quantity more descriptive.
>>> all = dict(
... a = Quantity('1ug'),
... b = Quantity('2mg'),
... c = Quantity('1.1ug)'
... )
>>> for n, v in all.items():
... print(f'{n} = {v}')
a = 1 ug
b = 2 mg
c = 1.1 ug
It provides many more features as well.
You can use a dictionary of prefices:
prefix = {"y":1e-24, "z":1e-21, "a":1e-18, "f":1e-15, "p": 1e-12,
"n":1e-9, "u":1e-6, "µ":1e-6, "m":1e-3, "c":1e-2, "d":0.1,
"h":100, "k":1000, "M":1e6, "G":1e9, "T":1e12, "P":1e15,
"E":1e18, "Z":1e21, "Y":1e24}
def meter(s):
try:
# multiply with meter-prefix value
return float(s[:-1])*prefix[s[-1]]
except KeyError:
# no or unknown meter-prefix
return float(s)
for a in ["1u", "2m", "1.1u", "42", "6k"]:
print(meter(a))
Result:
1e-06
0.002
1.1e-06
42.0
6000.0
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