Obtain specific part of URL

Question

I have the following jsp where I need to modify a specific part of my current url

String path = request.getRequestURL().toString();
...
response.sendRedirect("https://new.user.SAME.SAME/main.jsp");

I would like to take the XXX part of my current url and put it in the sendRedirect link.

For an example, if I am currently on https://old.user.domain.com/main.jsp , then the new link should be https://new.user.domain.com/main.jsp .

The only thing constantly changes is the user part. I currently use response.sendRedirect("/main.jsp") to redirect on the same site, but I can't seem to figure out a way to get the part between the dots.

Solved

String user = path.substring(path.indexOf("old.") + 4, path.indexOf(".domain"));
response.sendRedirect("https://new." + user + ".domain.com/main.jsp");

Answer 1

请求 URI是您要查找的 URL 的一部分：

request.getRequestURI()

Answer 2

Solved

String user = path.substring(path.indexOf("old.") + 4, path.indexOf(".domain")); response.sendRedirect(" https://new ." + user + ".domain.com/main.jsp");