A password consists of digits and Latin letters in any case; a password always follow by the "password" word (in any case), but they can be separated by any number of spaces and the colon: characters.
I try this regular expression
Pattern pattern = Pattern.compile("password\\s\\w*",Pattern.CASE_INSENSITIVE);
If text is
String text = "My email javacoder@gmail.com with password SECRET115. Here is my old PASSWORD: PASS111.\n";//scanner.nextLine();
We need to find SECRET115 and PASS111. Now program fails and cannot find pattern.
You may add an optional :
after password
, and match 0 or more whitespaces with \s*
:
password:?\s*(\w+)
See the regex demo .
Details
password
- a fixed string :?
- 1 or 0 colons \s*
- 0+ whitespaces (\w+)
- Capturing group 1: one or more word chars. String s = "My email javacoder@gmail.com with password SECRET115. Here is my old PASSWORD: PASS111.\n";
Pattern pattern = Pattern.compile("password:?\\s*(\\w+)", Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(s);
while (matcher.find()){
System.out.println(matcher.group(1));
}
Output:
SECRET115
PASS111
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