How to check whether or not a string consists of a single repeating digit using Python

Question

the code:

def repeatingDigits(digits): pattern = set(digits.lstrip("0")) print(pattern)

if len(pattern) > 1:
    return(False)

if len(pattern) == 1:
  return(True)

repeatingDigits("0111") ''TRUE'' repeatingDigits("0112") ''FALSE''

Answer 1

Use the regex: ^0*([1-9])\1*$

Explanation:

• ^ : begin searching at start of string
• 0* : search for any repeated 0's
• ([1-9]) : match digits other than 0 and remember it
• \1* : match one or more instances of the previously matched digit
• $ : end of string

The anchor tokens ^ and $ allow weeding out multiple occurrence of recurring digits. Python code:

import re
def repeatingDigits(digits):
    pattern = r"^0*([1-9])\1*$"
    return re.search(pattern, digits)

Answer 2

the code:

def repeatingDigits(digits): pattern = set(digits.lstrip("0")) print(pattern)

if len(pattern) > 1:
    return(False)

if len(pattern) == 1:
  return(True)

repeatingDigits("0111") ''TRUE'' repeatingDigits("0112") ''FALSE''