I have a C program that generates a number of matrices I want to store in CSV files, which I later make images and then a GIF out of. The program is working currently, but the way I have defined the filenames is awkward. Currently I hardcode it in like so:
char filenames[5][10] = {
"0.csv",
"1.csv",
"2.csv",
"3.csv",
"4.csv",
"5.csv"
};
Would there be a way to programmatically generate an array like this, say in a for loop? I have an intuition it would look something like this:
int num_files=10;
char** filenames;
int i;
for(i=0;i<num_files;i++) {
filenames[i] = malloc(something) /*some sort of memory allocation*/
filenames[i] = format("%d.csv",i); /*some sort of string formatting process*/
}
Thanks for the help.
char (*genArray1(size_t nfiles))[10]
/* can be also: void *genArray(size_t nfiles) */
{
char (*array)[10] = malloc(sizeof(*array)* nfiles);
if(array)
{
for(size_t fileno = 1; fileno <= nfiles; fileno++)
snprintf(array[fileno-1], sizeof(*array), "%zu.csv", fileno);
}
return array;
}
I came up with the following solution, In my program, I had to call a function multiple times which generated csv files. I defined the filename inside the loop as needed. This solution was based on the comments I received on this post.
/*generate csv files*/
int i;
char* filename; /*define the filename string array we will write to*/
int filename_len; /*we will need this when allocating memory*/
for (i=0;i<num_files;i++) {
/*generate filename.
this will be specific to your own code, depending on what you
want to name the files. My filenames are i.pgm (i + 4 characters),
Remember you also need to malloc another for the null terminator
at the end of char array*/
filename_len = snprintf(NULL,0,"%d",i) + 5; /*calculate filename len*/
filename = malloc(filename_len * sizeof filename[0]); /*malloc memory*/
sprintf(filename, "%d.pgm",i); /*sprintf(destination, format string, variables)*/
myfunction(filename, parameters); /*use filename as needed*/
free(filename); /*free memory*/
}
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