get distinct base on 2 or more Values from array in typescript

Question

I have an array as shown below.

I want this pattern:

I want to Get distinct "CityRef" and "City". then find all item in association with that.

Answer 1

Working TS playground .

interface GroupedItemsByCity {
  cityRef: number
  cityName: string,
  items: Array<{
    id: number,
    itemName: string
  }>
}

const groupedObject = returnObject.reduce<GroupedItemsByCity[]>((groupedArray, item) => {
    // New slimmer item to push later
    let refinedItem = {
        id: item.id,
        itemName: item.itemName
    }

    const matchedCity = groupedArray.find(city => city.cityRef === item.cityRef); // Check if the new structure already has a matching parent city for current item.
    if (matchedCity) {
        // If it does, push the item onto the existing city object.
        matchedCity.items.push(refinedItem)
        return groupedArray
    }

    // If it doesn't set up a new city and add the item to it
    groupedArray.push({
        cityRef: item.cityRef,
        cityName: item.cityName,
        items: [refinedItem]
    })

    return groupedArray
}, [])

console.log(groupedObject)